Talk:Summation chart: Difference between revisions

Revision as of 06:04, 5 October 2016

Proposed math code, please check/correct:

n = trunc[ 1-σ + sqrt[(σ-1)^2+2r] ]

\mathrm {n=\left\lfloor 1-\sigma +{\sqrt {(\sigma -1)^{2}+2r)}}\right\rfloor }

r = (n/2)(n+2σ-1)

\mathrm {r=\left({\frac {n^{2}+2n\sigma -n}{2}}\right)}

σ = (1/2)(1+2r/n-n)

\mathrm {\sigma =.5+{\frac {r}{n}}-{\frac {n}{2}}}

Obviously I didn't go for a direct translation, I tried to do some math. I'm sure it can be improved. VANKRASN39 (talk) 17:52, 4 October 2016 (CDT)

@@ Line 3: / Line 3: @@
 <div {{prettydiv|margin-right=70%}}>'''n = trunc[ 1-σ + sqrt[(σ-1)^2+2r] ]'''</div>
-{{Equation box|<math>\mathrm{n = \biggl\lfloor 1-\sigma + \sqrt{(\sigma - 1)^2 + 2r)} \biggr\rfloor}</math>}}
+{{Equation box|<math>\mathrm{n = \left \lfloor 1-\sigma + \sqrt{(\sigma - 1)^2 + 2r)} \right \rfloor}</math>}}
 <div {{prettydiv|margin-right=70%}}>'''r = (n/2)(n+2σ-1)'''</div>
-{{Equation box|<math>\mathrm{r = \biggl(\frac{n^2 + 2n\sigma - n}{2}\biggr)}</math>}}
+{{Equation box|<math>\mathrm{r = \left( \frac{n^2 + 2n\sigma - n}{2}\right)}</math>}}
 <div {{prettydiv|margin-right=70%}}>'''σ = (1/2)(1+2r/n-n)'''</div>